We bought one of our magazines earlier this week and I like to do the quizzes within them.
Below is one that will interest all you people out there.
There is a list of numbers that have to be fitted into a crossword style grid, and the number that is left over, when correctly completed, is the answer to the posed question.
If you use only the standard UK coinage of 1p, 2p, 5p, 10p, 20p, 50p, £1 & £2, how many different ways are there to make exactly £2?
No cheating or using Google etc. Only guesses or actual working it out.
Answer will be posted tomorrow night around this time, so the whole world gets a chance.
Post your guesses and we will see who is closes. No prizes, just satisfaction of being closest.
Best of luck to you all. You will need it.
Numismatic quiz question of the day. Well worth a look and guess
34 posts
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Posted:
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Goddamn maths! 
Alright, just by using my fingers:
1. 1x £2
2. 2x £1
3. 4x 50p
4. 10x 20p
5. 20x 10p
6. 40x 5p
7. 100 x 2p
8. 200 x 1p
Eliminating the £2:
9. 1x £1, + 2x 50p
10. 1x £1, + 5x 20p
11. 1x £1, + 10x 10p
12. 1x £1, + 20x 5p
13. 1x £1, + 50x 2p
14. 1x £1, + 100x 1p
.....
<Gave up here because of traumatic flashbacks to my maths GCSE>
Alright, just by using my fingers:
1. 1x £2
2. 2x £1
3. 4x 50p
4. 10x 20p
5. 20x 10p
6. 40x 5p
7. 100 x 2p
8. 200 x 1p
Eliminating the £2:
9. 1x £1, + 2x 50p
10. 1x £1, + 5x 20p
11. 1x £1, + 10x 10p
12. 1x £1, + 20x 5p
13. 1x £1, + 50x 2p
14. 1x £1, + 100x 1p
.....
<Gave up here because of traumatic flashbacks to my maths GCSE>
Posted:
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I didn't write it myself I just remembered that somebody who likes these kind of riddles and likes to code send me this python script a while ago. I just modified it to the conditions of this quest.
Just a summation with arrays and took 1.8 sec for a complete run it seems.
def Anzahl(S, m, n ):
if (n == 0):
return 1
if (n < 0):
return 0;
if (m <=0 and n >= 1):
return 0
return Anzahl( S, m - 1, n ) + Anzahl( S, m, n-S[m-1] );
Muenzen = [1, 2, 5, 10 , 20, 50, 100, 200]
m = len(Muenzen)
print(Anzahl(arr, m, 200))
Just a summation with arrays and took 1.8 sec for a complete run it seems.
def Anzahl(S, m, n ):
if (n == 0):
return 1
if (n < 0):
return 0;
if (m <=0 and n >= 1):
return 0
return Anzahl( S, m - 1, n ) + Anzahl( S, m, n-S[m-1] );
Muenzen = [1, 2, 5, 10 , 20, 50, 100, 200]
m = len(Muenzen)
print(Anzahl(arr, m, 200))
Posted:
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Ok, it's answer time. A little early, but its hot in my office, so I thought anyone who wanted to have a go, would have done so by now.
Attached are two photographs.
Left-the whole quiz, with numbers to left, crossed out if used and the crossword grid filled in.
Right-The list of numbers, clearly showing the one that has not been used, which is the answer.
Attached are two photographs.
Left-the whole quiz, with numbers to left, crossed out if used and the crossword grid filled in.
Right-The list of numbers, clearly showing the one that has not been used, which is the answer.
I'm just a collector of coins, not a slave to it, unless I am in a coin shop.
For all you banknote collectors. Link to my swap list.
https://colnect.com/en/banknotes/list/swap_list/COINMAN1
For all you banknote collectors. Link to my swap list.
https://colnect.com/en/banknotes/list/swap_list/COINMAN1
Posted:
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ROMA AETERNA
Posted:
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Well goddamn, that's a lot of combinations. Glad I quit where I did. 
Posted:
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Quote: "druzhynets"The famous coin change problemThere is a much more elegant algorithm. Here it is, in Python:
https://www.geeksforgeeks.org/dynamic-programming-set-7-coin-change/
Quotetarget = 200
coins = [1, 2, 5, 10, 20, 50, 100, 200]
ways = [1] + [0]*target
for coin in coins:
for i in range(coin, target+1):
ways[i] += ways[i-coin]
print ("There are", ways[target], "ways to make", target)[/i]
[i][i]The answer it produces is (runs in a fraction of a second): There are 73682 ways to make 200
[/i][/i]
HoH
Posted:
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That is a brain fryer.
How about for spice, we assume its 1984 and we also have the ½p coin, what would that take it up to?
How about for spice, we assume its 1984 and we also have the ½p coin, what would that take it up to?
I love coins. Especially silver, gold and anything really old.
Member of the Royal Numismatic Society of New Zealand and the Auckland Numismatic Society
Member of the Royal Numismatic Society of New Zealand and the Auckland Numismatic Society
HongKongCoinCollector
Joined: 27 Feb 2019
Posts: 195
Posts: 195
Posted: 9 May 2019, 14:53
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Edited: 9 May 2019, 14:56
Edited: 9 May 2019, 14:56
Posted:
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Edited:
Edited:
Quote: "Moneytane"That is a brain fryer.You want spice? I'll give you spice.
How about for spice, we assume its 1984 and we also have the ½p coin, what would that take it up to?
Farthing, halfpenny, penny, twopence, threepence, groat, sixpence, shilling, florin, half crown, crown, sovereign.
Make £2 from that.
If anyone's complaining I'll throw in the 1 1/2 pence in there.
光復香港 時代革命
五大訴求 缺一不可
Liberate Hong Kong, Revolution of our times
五大訴求 缺一不可
Liberate Hong Kong, Revolution of our times
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