How much gold is on this coin [solved]

I looked online and it said it was 24 karat gold plated zinc, but I don’t know how much gold is on it. If you know how much, can you tell me?

These type coins have negligable amounts of gold plating on them. Typically 0.5-2.5 microns thick and only the manufacturer knows for certain. It is all about the marketing appeal of the word GOLD to imply added value. The term piques everybodys interest and the marketing tactic is effective. Looks beautiful but no real value added. 

If description really says “24 karat gold plated”.

Imagine that you go to meat store, point at lump of meat wrapped in plastic and ask seller how much 100% pure plastic is in there.

24 karat should be use to define gold purity. Not purity of gold plating on zinc.

Yea that makes sense, thanks for the analogy

Do you at least know how much the whole coin weighs, I couldn’t find that either.

It is a copy of 1 oz silver variant. Silver to zinc weight ratio is 10 to 7. Should be around 21 gram, if they kept same size and thickness.

Gold plated silver variant is for sale on ebay along with certificate and other info.

The value and amount of gold that is in microns is up to two dollars, approximately.

MIMAEL

The value and amount of gold that is in microns is up to two dollars, approximately.

I calculated it and if the gold plating is 1.5 micrometers thick, given that the diameter is 39 millimeters and the height is 3 millimeters, the volume of the gold on it is about 6 cubic millimeters (I looked up a calculator for the volume of a hollow cylinder, but the calculator thinks of a hollow cylinder as something in the shape of a roll of toilet paper, not one where the center part is completely surrounded, so it gave me the result 5.511 cubic millimeter, so I rounded it up to count for the missing parts). So then I used a calculator to calculate its mass based on its volume and density (19.32 g/cm3 for pure gold), which gave me 0.11592 grams. The current price of gold per gram is 89.72 USD, which means that the amount of gold in there is worth about $10.40. And since the total weight of the coin is about 21 grams, about 0.5% of the coin’s weight is gold.

I know it’s a lot just to figure out the amount of gold in a coin, but I like to know things like that

don't go shopping for plastic in meats stores

Unless if you want to know how much microplastics you’re digesting

Pluto2181930

MIMAEL

The value and amount of gold that is in microns is up to two dollars, approximately.

I calculated it and if the gold plating is 1.5 micrometers thick, given that the diameter is 39 millimeters and the height is 3 millimeters, the volume of the gold on it is about 6 cubic millimeters (I looked up a calculator for the volume of a hollow cylinder, but the calculator thinks of a hollow cylinder as something in the shape of a roll of toilet paper, not one where the center part is completely surrounded, so it gave me the result 5.511 cubic millimeter, so I rounded it up to count for the missing parts). So then I used a calculator to calculate its mass based on its volume and density (19.32 g/cm3 for pure gold), which gave me 0.11592 grams. The current price of gold per gram is 89.72 USD, which means that the amount of gold in there is worth about $10.40. And since the total weight of the coin is about 21 grams, about 0.5% of the coin’s weight is gold.

Let me remember my math from school and correct you a bit.:)

We will need to find the volume of gold in mm³. It consists of 2 surfaces and an edge.

To find the volume of the surfaces:

Area = πr² = 3.1416 x 19.5 mm x 19.5 mm = 1,194.6 mm²

Volume = area x height (0.0015 mm as an average you suggested) = 1,194.6 x 0.0015 = 1.79 mm³

To find the volume of the edge:

Circumference (length) = 2πr = 2 x 3.1416 x 19.5 mm = 122.5 mm

Volume = length x width x height = 122.5 x 3 x 0.0015 = 0.55 mm³

Total volume will be: 2 x surface volume + edge volume = 2 x 1.79 + 0.55 = 4.13 mm³

The weight of gold per mm³ is 0.01932 g.

4.13 mm³ x 0.01932 g = 0.08 g.

The cost of gold is: 0.08 g x $89.72 = $7.18.

If the gold plating is the minimum (0.5 microns), it will be $7.18/3 = $2.39.

% of the total weight of the token is: 0.08/21 = 0.38%.

It was fun calculating:) It was one of those times when I actually used school geometry. But I am still waiting for a day to apply the trigonometry for the first time that we studied so hard.😄

That seems about right. I went in between instead of the minimum so we got different results

Gold plate minimums typically can be 0.04 microns.  That thickness will give a completely gold coloring.

rsirian1

Gold plate minimums typically can be 0.04 microns.  That thickness will give a completely gold coloring.

And what do you think is the purity of such gold?

I claim that the applied mixture is never 999/1000 purity of gold, i.e. 24 karats. Maybe 450/1000. At most, maybe 750/1000

Ivan

I would assume if it were electroplated to those thicknesses then it would be pure gold.

At the utmost a dollar but probably more likely 15-30 cents. You are calculating with near jewellery thicknesses that are overkill for objects like these trinkets. You want to peddle money with these objects not spend it all on raw material.

Also why is this thread in coins?

rsirian1

I would assume if it were electroplated to those thicknesses then it would be pure gold.

Actually yes you are right. But I don't know much about gold electrolysis

Ivan

Ok so I measured its weight using a homemade scale, and it weighs about as much as this coin I have N#452814

I've lost track. What exactly is your question? Do you now suspect it's gold plated silver?

No. I’m just saying that it weighs as much as the other coin

The original question was how much gold is on the coin

The answer is still a negligable and insignificant amount of gold.